If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4y^2-64y+255=0
a = 4; b = -64; c = +255;
Δ = b2-4ac
Δ = -642-4·4·255
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-4}{2*4}=\frac{60}{8} =7+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+4}{2*4}=\frac{68}{8} =8+1/2 $
| (x+5)(x+2)-3(4x-3)=(x-25) | | 8(4a-4)-1=(14-8a) | | h/8=16/30 | | 3x/8+5=17 | | 3/n=4/18 | | X/7+x/9=72 | | 6=-6x+ | | 2(x-5)-8(x-6)=10 | | 3(-2x-1)=-5x+7 | | 3975=(p)+(p)(0.053)(5) | | 3795=(p)+(p)(5.3)(5) | | 3975=(p)+(p)(5.3)(5) | | 7(x-2)+3x+6=0 | | -3=1(-4)+b | | 10t=60(t-1) | | 2n-3/3n-8/4=n+1/3 | | 3(w+5)=-9 | | 3/4x-x=9/16x-3/4x | | -5/3=5/2w-7/4 | | 7/6x=16 | | 3(2^(9x-8))-7=14 | | y/12+13=0 | | -3m=8m-16 | | -9.4r=34.78 | | -3.6r=-12.24 | | p-38.56=114.44 | | 28.45=x-18.83 | | a+64=134 | | 5(9x+2)=-7(6-5x) | | -8=2x/9 | | 5(9x+2)=7(6-5x) | | -3/8x=-5 |